t-test for Mean

t-test for mean

In this tutorial we will explain the six steps approach used in hypothesis testing to test hypothesis about the population mean when the population standard deviation is unknown and how to find t-test for mean in statistics.

One sample t test for mean

Let $X_1, X_2, \cdots, X_n$ be a random sample from a normal population with mean $\mu$ and unknown variance $\sigma^2$.
Let $\overline{x}=\frac{1}{n} \sum x_i$ be the sample mean and $s^2 =\frac{1}{n-1} \sum (x_i -\overline{x})^2$ be the sample variance.

Assumptions

a. The population from which, the sample drawn is assumed as Normal distribution.

b. The population variance $\sigma^2$ is unknown.

Step by Step Procedure

We wish to test the null hypothesis $H_0 : \mu = \mu_0$, where $\mu_0$ is the specified value of the population mean.

The standard error of mean is

$$ \begin{aligned} SE(\overline{x}) & = \frac{\sigma}{\sqrt{n}}=\frac{s}{\sqrt{n}} \end{aligned} $$

Step 1 State the hypothesis testing problem

The hypothesis testing problem can be structured in any one of the three situations as follows:

Situation Hypothesis Testing Problem
Situation A $H_0: \mu=\mu_0$ against $H_a : \mu < \mu_0$ (Left-tailed)
Situation B $H_0: \mu=\mu_0$ against $H_a : \mu > \mu_0$ (Right-tailed)
Situation C $H_0: \mu=\mu_0$ against $H_a : \mu \neq \mu_0$ (Two-tailed)

Step 2 Define the test statistic

The test statistic for testing above hypothesis is

$$ \begin{eqnarray*} t & =& \frac{\overline{x}-\mu}{SE(\overline{x})}\\ & = & \frac{\overline{x}-\mu_0}{s/\sqrt{n}} \end{eqnarray*} $$

The test statistic $t$ follows Students' $t$ distribution with $n-1$ degrees of freedom.

Step 3 Specify the level of significance $\alpha$.

Step 4 Determine the critical values

For the specified value of $\alpha$ determine the critical region depending upon the alternative hypothesis.

  • left-tailed alternative hypothesis: Find the $t$-critical value using

$$ \begin{aligned} P(t<-t_{\alpha,n-1}) & = \alpha. \end{aligned} $$

  • right-tailed alternative hypothesis: $t_\alpha$.

$$ \begin{aligned} P(t>t_{\alpha, n-1}) & = \alpha. \end{aligned} $$

  • two-tailed alternative hypothesis: $t_{\alpha/2}$.

$$ \begin{aligned} P(|t| > t_{\alpha/2,n-1}) &= \alpha. \end{aligned} $$

Step 5 Computation

Compute the test statistic under the null hypothesis $H_0$ using equation

$$ \begin{aligned} t_{obs} & = \frac{\overline{x}-\mu_0}{s/\sqrt{n}} \end{aligned} $$

Step 6 Decision (Traditional Approach)

Traditional approach is based on the critical value.

  • For left-tailed alternative hypothesis: Reject $H_0$ if $t_{obs}\leq -t_{\alpha,n-1}$.
  • right-tailed alternative hypothesis: Reject $H_0$ if $t_{obs}\geq t_{\alpha,n-1}$.
  • two-tailed alternative hypothesis: Reject $H_0$ if $|t_{obs}|\geq t_{\alpha/2, n-1}$.

OR

Step 6 Decision ($p$-value Approach)

It is based on the $p$-value.

Alternative Hypothesis Type of Hypothesis $p$-value
$H_a: \mu<\mu_0$ Left-tailed $p$-value $= P(t\leq t_{obs})$
$H_a: \mu>\mu_0$ Right-tailed $p$-value $= P(t\geq t_{obs})$
$H_a: \mu\neq \mu_0$ Two-tailed $p$-value $= 2P(t\geq abs(t_{obs}))$

If $p$-value is less than $\alpha$, then reject the null hypothesis $H_0$ at $\alpha$ level of significance, otherwise fail to reject $H_0$ at $\alpha$ level of significance.

Endnote

In this tutorial, you learned the $t$-test for testing population mean and the assumptions for $t$-test for testing population mean. You also learned about the step by step procedure to apply $t$-test for testing population mean.

To learn more about other hypothesis testing problems, hypothesis testing calculators and step by step procedure, please refer to the following tutorials:

Let me know in the comments if you have any questions on $t$-test for population mean and your thought on this article.

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